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(Josh showed me this one last month:)

Three men went to a hotel one night.
The man at the front desk charged them thirty dollars for the room, and each man gave $10.
Later on, the front desk guy realized he had overcharged the men by $5, so he sent the bellhop to the men's room with five $1 bills. On the way, the bellhop was trying to figure out how to distribute the $5, and he decided to give each man $1 and keep the last $2 as a tip. So he did so.
So after all was said and done, each man actually paid $9 for the room. $9 + $9 + $9 = $27. Add two for the bellhop's tip and you get $29.
Where's the other dollar?


( 5 comments — Leave a comment )
Aug. 12th, 2001 03:26 pm (UTC)
That's a good one
I'm sure you guys already know the answer, but I think this is it:

This question seems not so much a problem of math, but a problem of grammar. The room actually cost $25 ($5 less the incorrect $30). Thus, each man paid $9 for the room, making a total of $27. From that point you *subtract* the bellhop's tip and get a total of $25 -- the cost of the room.

But the REAL problem is that a genuine bellhop would've made off with the whole 5 bucks.
Aug. 12th, 2001 06:01 pm (UTC)
Re: That's a good one
I hate math.
Aug. 12th, 2001 06:09 pm (UTC)
Re: That's a good one
How sad! Math likes you.

Poor math.
Aug. 12th, 2001 09:14 pm (UTC)
Re: That's a good one
No, math hates me too. He told me.
Aug. 12th, 2001 10:01 pm (UTC)
The adding up is all wrong!
At the end you add up the 9+9+9 = 27 - $2 for the Bell hop give you the 25 they paid for the room!
To get the $30 the hotel has 25 each guy has 1 and the bellhop has 2!
( 5 comments — Leave a comment )